Wednesday, March 5, 2014

QA Problem 1

There lived a rich farmer who before his death, divided all his property equally among all his daughters. The property was in the form of gold bars, silver bars and cash. The gold bars were worth Rs.4000/- each and silver bars were worth Rs.1000/- each. The property was divided as follows:
First daughter received 20% of the total property in the form of gold bars and Rs.25,000/- in cash . The second daughter received 20% of the total remaining property in the form of silver bars and Rs.50,000/- cash. Each of the succeeding daughters received equal number of gold and silver bars worth 20% of the total remaining property and cash which was Rs.25000/- more than the cash received by previous daughter.

[Q1] What was the total value of the property?
 a) Rs.10 lakhs         b) Rs.20 lakhs        c) Rs.5 lakhs         d) Rs.60 lakhs

[Q2] How many daughters were there in all?
a) 5 b) 6 c) 3 d) 4

[Q3] How many gold bars were there in all?
a) 40 b) 24 c) 25 d) 26

[Q4] How many silver bars did the third daughter receive?
a) 20 b) 10 c) 30 d) 25

Detailed solution is given on the comment section.